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FizzBuzz is a classic programming challenge that prints numbers from 1 to 100, replacing multiples of 3 with “Fizz”, multiples of 5 with “Buzz”, and multiples of both with “FizzBuzz”.

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Simple implementation

This implementation uses a for loop with a range and string concatenation: 
for n in 1..101 {
    let result = "";

    if n % 3 == 0 {
        result += "Fizz";
    }

    if n % 5 == 0 {
        result += "Buzz";
    }

    if result == "" {
        result = n;
    }

    println(result);
}

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How to run

Save the code to a file called fizzbuzz.walrus and run it: 
walrus fizzbuzz.walrus

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Expected output

1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
...

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Function-based implementation

You can also implement FizzBuzz as a reusable function that returns a string: 
fn fizzbuzz : n {
    let output = "";
    for i in 1..(n + 1) {
        let result = str(i);
        if i % 15 == 0 {
            result = "FizzBuzz";
        } else if i % 3 == 0 {
            result = "Fizz";
        } else if i % 5 == 0 {
            result = "Buzz";
        }
        output = output + result + " ";
    }
    return output;
}

println(fizzbuzz(20));

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Output

1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz 19 Buzz

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Key concepts

  • Ranges: 1..101 creates a range from 1 to 100 (exclusive end)
  • Modulo operator: % checks for divisibility
  • String concatenation: += appends to strings
  • Type flexibility: Variables can hold different types (string or integer)

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